If I walk at 5km/hr, I reach 5 min before the arrival of the bus. How far the is the school from his house?Ģ) If I walk at 4km/hr, I miss the bus by 10 min. Next day increases his speed by 1kmph and reaches the school 6 minutes early. Here they are same (30 Mins=30 Mins) So the distance is 60 Kmġ)Starting from his house one day ,a student walks at a speed of 2(1/2)kmph and reaches his school 6minutes late. Therefore the distance between his home and office is 60Km. Here the difference between the time taken here is 30 mins(1hr 30 mins and 1hr is 30 mins) and The difference between 8.50 AM – 9.20 AM=30 minutes is same. The difference between 8.50 AM -9.20 AM=30 minutes. The difference between the time taken here is 30 mins(1hr 30 mins and 1hr is 30 mins) Here we don’t know the distance between them so lets take L.C.M of speed and consider it as the total distance Let us consider a man starts from his home by 9.00A.M. Then what is the distance between his home and his office? If a man walks from home to his office at the rate of 40km/hr and he is late by 20 minutes and if man goes to his office from home by riding a bike at the rate of 60km/hr then he reaches the office 10 minutes early. The total journey was performed by him in 10hr.Find the distance from A to B?Ī) 100km b) 110km c) 120km d) 125km #2 TYPE 2 : BASED ON REACHING THE DESTINATION EARLY AND LATE: A man travels on a Scooter from A to B at a speed of 30km/hr and returns back from B to A at 20km/hr. A increases his speed by 5km/hr then time taken reduced by 20%.What is the initial speed of journey?Ī) 10km/hr b) 15km/hr c) 20km/hr d) 25km/hrĢ.A Car travelling with 5/7 of the actual speed covers 42km in 1hr 40min 48sec.Find the actual speed of the car?Ī) 17km/hr b) 32km/hr c) 31km/hr d) 35km/hrģ. Then at what speed he should ride in order to reach the destination less than 3 hrs than his usual speed express in m/sec?ĩ0km/hr=90*(5/18)=25m/sec Try & Practice Questions:ġ. If a man rides a distance of 540km at the rate of 60Km/hr. If Speed increases then Distance is also increases,If Speed decreases then Distance also decreases) #1 TYPE 1: BASED ON TIME ,DISTANCE AND SPEED: If Time is Constant then, the ratio between Distance and Speed is directly proportional to each other. If Distance is Constant then, Time(T1 &T2) and Speed(S1 and S2) is inversely proportional to each other S1/S2=T2/T1 If the unit is in m/sec and it is converted into km/hr by multiplying it with 18/5,ġ km/hr is converted into 1m/sec by *(5/18)ġ m/sec is converted into 1 Km/hr by *(18/5) PROPORTIONAL: If the unit is in km/hr and it is converted into m/sec by multiplying it with 5/18, Average Speed = Total Distance/Total TimeĪverage Speed (when distance is same and there is 2 speed) =2xy/(x+y)Īverage Speed (when distance is same and there is 3 speed) =3xyz/(xy+yz+zx)
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